# 字典的创建 # dict1 = {} # print(type(dict1)) # # dict2 = {
  #         'name':'汪峰', #         'sex':'男', #         'hiredate':'1997-10-20' #         } # print(dict2) # # dict3 = dict(name = 'eric',age = 28) # print(dict3) #  取值操作 # employee = {
  #         'name':'汪峰', #         'sex':'男', #         'grade':'A', #         'hiredate':'1997-10-20', #         'salary': 1000, #         'welfare':100 #         } # name = employee['name'] # print(name) # # sex = employee.get('sex') # print(sex) # # dept = employee.get('dept','其他部门') # print(dept) # in 成员运算符  判断 key 是否存在 # print('name' in employee)  # True # print('dept' in employee)  # False # print('dept' not in employee)  # True # 遍历字典 # 汪峰 # 男 # 1997-10-20 # for key in employee: #     v = employee[key] #     print(v) # name 汪峰 # sex 男 # hiredate 1997-10-20 # for k,v in employee.items(): #     print(k,v) # 单个更新 # employee['grade'] = 'B' # print(employee) # # 多个更新 # employee.update(salary = 1200, welfare = 150) # print(employee) # # # 新增 # employee['dept'] = '研发部' # print(employee) # # #  删除操作 # employee.pop('dept') # print(employee) # #  删除操作  删除最后一个 kv # employee.popitem() # print(employee) # # # 清空字典 # employee.clear() # print(employee) # emp1 = {'name':'jacky','grade':'B','hiredate':'1989-10-12'} # emp2 = {'name':'Lily','grade':'A','hiredate':'1989-10-12'} # # # setdefault 设置默认值 存在就忽略 不存在就创建 # emp2.setdefault('grade','C') # print(emp2) #  获取字典的视图 # k = emp1.keys() # # dict_keys(['name', 'grade']) # print(k) # # v = emp1.values() # # dict_values(['jacky', 'B']) # print(v) # # items = emp1.items() # # dict_items([('name', 'jacky'), ('grade', 'B')]) # print(items) # 格式化字符串 # emp_str = "姓名:{name},评级:{grade},入职时间{hiredate}".format_map(emp1) # print(emp_str) # 散列值 # h1 = hash("dabc") # # print(h1) # # h2 = hash("1231231") # # print(h2) # 例子 source = "12345,jace,ercd,php,5000$2345,clead,ercd,dfd,5000$22345,clead,ercd,dfd,5000$32345,clead,ercd,dfd,5000" employee_list = source.split("$") print(employee_list) all_emp = {} for i in range(0,len(employee_list)):     # print(i)     e = employee_list[i].split(",")     # print(e)     employee = {'no':e[0],'name':e[1],'www':e[2],'jod':e[3],'salary':e[4]}     print(employee)     all_emp[employee['no']] = employee print(all_emp) empno = input('编号:') if empno in all_emp:     emp = all_emp.get(empno)     print(emp); else:     print('编号不存在')